Skip to main content

C Program to find out the biggest of three numbers using Nested if Statement.

 C Program to find out the biggest of three numbers using Nested if Statement.


In this example we will learn how to find the biggest of three numbers using Nested if statement.


LOGIC OF THE BIGGEST OF THREE NUMBERS:


  • At first we have declared three variables a,b and c and we have stored the numbers inputted by the user in this three variables.


  • Then we have to check if the value of a greater than b then it will check if a greater than c if it is greater then it will print the value of a is the biggest of the three numbers and if it is not greater than it will print c is the biggest of three numbers. If the value of a not greater than b then it will not execute the above statements 

  • Then it will move to the second statement that is else if and will check if b greater than a if it is true then it will check if b greater than c if it is true it will print the value of b is the biggest of the three numbers if not then it will print the value of c is the biggest of three numbers.   


PROGRAM:

#include<stdio.h>
#include<conio.h>
void main()
{
    int a,b,c;
    printf("Enter the three Numbers :");
    scanf("%d%d%d",&a,&b,&c);
    if(a>b)
    {
        if(a>c)
            printf("%d is the biggest of the three numbers.",a);
        else
            printf("%d is the biggest of the three numbers.",c);
    }
    else if(b>a)
    {
        if(b>c)
            printf("%d is the biggest of the three numbers.",b);
        else
            printf("%d is the biggest of the three numbers",c);
    }
    getch();
}



OUTPUT:

C Program to find out the biggest of three numbers using Nested if Statement.


NESTED IF STATEMENT:


Nested if Statement means that if/else statement inside the body of another if statement. 


  • The Syntax of nested if statement is:

         if(expression)

{

if(expression)

statement;

else

statement;

}

else

statement;


  • Example of nested if statement:

if(a<=b)

{

if(a<b)

printf("%d<%d\n",a,b);

else

printf("%d=%d\n",a,b);

}

else

printf("%d>%d\n",a,b);

Here, in this example we have checked if a<=b if this statement is true then we will check if a<b if this is also true it will print (a<b) otherwise it will print (a=b). Else if a<=b is not true then it will print (a>b).

Labels:

Comments

Post a Comment

Please do not spam any link

Popular posts from this blog

C program to calculate area of a circle using function.

C program to calculate area of a circle. In this example we will learn to calculate the area of a circle. Here in this program we will use 3.14 as the value of pi.  The formula to calculate the area of a circle is:                                                         area=   π  r² Flowchart To Calculate the Area of a Circle: PROGRAM: #include <conio.h> #include <stdio.h> int   main () {      float   radius , area ;      printf ( "Enter the radius of the circle : " );      scanf ( "%f" ,& radius );      area = 3.14 * radius * radius ;          printf ( "Area of the circle is : %.2f" , area );  ...
Post a Comment
Read more

C Program to Calculate the Factorial of a number using Function

  C Program to Calculate the Factorial of a number using Function.     In this example, we will calculate the factorial of a number using function. Here we have used functions with Arguments and return value to perform this operation. We have declared a user-defined function fact which is called in the main function when printing the result. What is a Factorial of  a Number?      The factorial of a number is the product of all positive integers less than, equal to n. Factorial is denoted by the symbol '!'. Formula of factorial is n!=n x (n-1)! For example: 6!= 6 x 5 x 4 x 3 x 2 x1    = 720 PROGRAM TO CALCULATE THE FACTORIAL OF A NUMBER USING FUNCTION #include <stdio.h> #include <conio.h> int   fact ( int ); void   main () {      int   n ;      printf ( "Enter the number : " );      scanf ( " %d " ,& n );   ...
Post a Comment
Read more

C Program to find the sum of the series 1^2+2^2+3^2+…..+n^2

C Program to find the sum of the series  1 2 +2 2 +3 2 +…..+n 2 Enter the end limit at the runtime.       In this example, we calculate the sum of the above mentioned series till the end-limit entered by the user. We have used built-in function pow(x,y) to find the power of the given number.     Here in the output we have entered the value of end-limit as number 7 which gives a sum of 140.    PROGRAM #include <stdio.h> #include <math.h> #include <conio.h> void   main () {      int  n,sum= 0 ,i;      printf ( "Enter the end limit :" );      scanf ( " %d " ,&n);      for (i= 1 ;i<=n;i++)     {         sum=sum+ pow (i, 2 );     }      printf ( "Sum of the series is :  %d " ,sum);  ...
Post a Comment
Read more

C program to reverse a number entered by the user

 C program to reverse a number entered by the user     In this example, we will display the reverse of a number entered by the user. Here, in the output we have entered a number 472 whose reverse will be displayed in the screen. C PROGRAM TO REVERSE A NUMBER ENTERED BY THE USER: #include <stdio.h> #include <conio.h> void  main() {      int  x,y=0,r;     printf( "Enter a number : " );     scanf( "%d" ,&x);      while (x!=0)     {         r=x%10;         y=y*10+r;         x=x/10;     }     printf( "Reverse is : %d" ,y);     getch(); } OUTPUT TO REVERSE A NUMBER ENTERED BY THE USER:      Enter a number: 472      Revers...
Post a Comment
Read more

C Program to Check a given Number is Armstrong or Not

 C Program to Check a given Number is Armstrong or Not.     In this example, we will check a number entered by the user whether it is an Armstrong number or not. To solve this program we should have a proper concept on Armstrong number, while loop and if-else statement. What is an Armstrong Numer?           An Armstrong number is a positive number that is equal to the sum of the power of the digits. For Example: Let's take 153:  1 3  + 5 3  + 3 3                                                                    = 1 + 125+ 27                                                     ...
Post a Comment
Read more