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C Program to Check a given Number is Armstrong or Not

 C Program to Check a given Number is Armstrong or Not.

    In this example, we will check a number entered by the user whether it is an Armstrong number or not. To solve this program we should have a proper concept on Armstrong number, while loop and if-else statement.


What is an Armstrong Numer?

        An Armstrong number is a positive number that is equal to the sum of the power of the digits.

For Example: Let's take 153: 13 + 53 + 33 

                                                    = 1 + 125+ 27 

                                                    = 153

    which means 153 is an Armstrong number.


PROGRAM

#include<stdio.h>
#include<conio.h>
int main()
{
    int num,a,r,sum=0;
    printf("\n Enter the Number : ");
    scanf("%d",&num);
    a=num;
    while(a>0)
    {
        r=a%10;
        sum=sum+r*r*r;
        a=a/10;
    }
    if(num==sum)
    {
        printf("\n%d is an Armstrong Number.",num);
    }
    else
    {
        printf("\n%d is Not an Armstrong Number.",num);
    }
    return 0;
}


OUTPUT

C Program to Check a given Number is Armstrong or Not

NOTE: You Can Comment Your Code if you have solved differently and we will pin it in the comment section.  Let's Learn together. 


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You Learn, I Learn together We Learn.

 


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